The frequency which, under the sampling theorem, must be exceeded by the sampling frequency is called the Nyquist rate. Determine the Nyquist rate corresponding to each of the following signals: (a) x(t)=1+cos (2,000 π t)+sin (4,000 π t) (b) x(r)=(sin (4,000 π t))/(π t) (c) x(t)={ .(sin (4,000 π t))/(π t))^2 .

Channel Capacity: Nyquist and Shannon Limits - SlideServe

Question #2:a) Calculate the minimum sampling rate to avoid aliasing when a continuous-time signal is given by xt = 5cos(400nt).b) Calculate the Nyquist rate for sampling when a continuous-time signal is given by xt = 5cos(100xt) 10cos(200nt) - 15cos(300xt).