Weibull Distribution: From an analysis of wind speed data (hourly interval average, taken over a one year period), the Weibull parameters are determined to be c = 8 m/s and k = 1.5 at a potential wind turbine site.Recall from lecture, the Weibull probability distribution function is given by:((k)/(c))((U)/(c))^k-1exp[-((U)/(c))^k]a) Plot p(U) v.s. Ub) What is the average wind speed (U̅) at this site?Manwell textbook gives a series representation to calculate Γ(x).In Excel one can use two excel f

The Weibull distribution is defined as:

Weibull Lognormal Distribution

Problem 43.5 Weibull distribution: From an analysis of wind speed data (hourly interval average, taken over a 1year period), the Weibull parameters are determined to be c = 6 m/s and k = 1.8 at a potential WTsite.The Weibull PDF is given by p(U) = ((k)/(c))((U)/(c))^k-1[-((U)/(c))^k]a. Estimate the number of hours per year that the wind speed will be between Ub = 6.5 m/s and UA =7.5 m/s during the year.b. Estimate the number of hours per year that the wind speed is above 16 m/s.