Move one step at a time to correctly handle obstacles At every step, we calculate the squared distance from origin and keep track of the maximum.

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// TIME: O(n^2.81) vs naive O(n³) // RECURRENCE: T(n) = 7T(n/2) + O(n²) → O(n^log₂7) ≈ O(n^2.81) ...

So, you’re looking to get better at coding interviews, huh? Maybe you’ve heard about LeetCode and feel a bit lost. It’s ...