First, we need to find which number when substituted into the equation will give the answer zero. \(f(1) = {(1)^3} + 4{(1)^2} + (1) - 6 = 0\) Therefore \((x - 1)\)is a factor. Factorise the quadratic ...

The paper discusses both theoretical properties and practical implementation of product integration rules of the form $$\int^\infty_{-\infty} k(x)f(x) dx \approx \sum ...

A research team has experimentally calculated the Jones polynomial based on the quantum simulation of braided Majorana zero ...